Timeline for Sum of two consecutive squares equals difference of two consecutive cubes
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 23, 2017 at 11:34 | answer | added | individ | timeline score: 1 | |
| Aug 22, 2017 at 21:02 | comment | added | Yaakov Baruch | Happy birthday! | |
| Aug 22, 2017 at 16:07 | comment | added | Michael Lugo | In particular the ratio between consecutive values of $a$ converges to $5 + 2\sqrt{6}$. $485/198$ is one of the convergents to the continued fraction of $\sqrt{6}$ and hence is a good approximation to $\sqrt{6}$, and $5 + 2(485/198) = 980/99$. | |
| Aug 22, 2017 at 15:34 | answer | added | Dr. Pi | timeline score: 9 | |
| Aug 22, 2017 at 15:31 | vote | accept | Ernest Davis | ||
| Aug 22, 2017 at 15:21 | comment | added | Nathaniel Johnston | See A219113 in the OEIS. There is a closed formula for this sequence and a reference or two that should be useful. | |
| Aug 22, 2017 at 15:12 | answer | added | yarchik | timeline score: 10 | |
| Aug 22, 2017 at 15:07 | comment | added | Christian Gaetz | What is it, exactly, that is "striking" and needs explaining? | |
| Aug 22, 2017 at 14:58 | history | asked | Ernest Davis | CC BY-SA 3.0 |