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Aug 20, 2017 at 16:29 history edited Ulrich Pennig CC BY-SA 3.0
added details about crossed product
Aug 20, 2017 at 16:19 vote accept worldreporter
Aug 20, 2017 at 16:19 comment added worldreporter All right! I think I get it now. Tanks a lot!
Aug 20, 2017 at 15:58 comment added Ulrich Pennig Note that $t$ is not an element of $A$, i.e. the automorphism does not have to be inner from the start. However, the crossed product is defined in such a way that the automorphism becomes inner by adding another element $t$ that satisfies $tat^* = \alpha(a)$.
Aug 20, 2017 at 15:54 comment added worldreporter Thanks for your answer! I see that if we have a $t$ such that $tat^*=\alpha(a)$ elements of the above polynomial form are exactly the elements of the crossed product. But why is every automorphism of this form? Is this a general property of the multiplier algebra?
Aug 20, 2017 at 12:54 history answered Ulrich Pennig CC BY-SA 3.0