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Aug 19, 2018 at 23:09 history undeleted j.c.
Stefan Kohl
Yemon Choi
Aug 18, 2018 at 0:01 history deleted CommunityBot Scheduled: RemoveAbandonedQuestions
Aug 17, 2017 at 10:54 comment added reuns $\hat{b}(\xi) = C\text{sign}(\xi) -C \hat{\beta} \ast \text{sign}(\xi)$ so $\hat{b}$ is bounded (and continuous away from $\xi=0$). For the rate of decrease $b^{(k)} \in L^2$ so $\xi^k \hat{b} \in L^2$ for $k\ge 0$.
Aug 17, 2017 at 6:50 history edited Patch CC BY-SA 3.0
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Aug 17, 2017 at 6:26 history edited Patch CC BY-SA 3.0
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Aug 17, 2017 at 1:47 history asked Patch CC BY-SA 3.0