Timeline for Confidence intervals for the endpoints of the uniform distribution
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Aug 15, 2017 at 23:48 | vote | accept | Oliver | ||
| Aug 15, 2017 at 23:42 | comment | added | Oliver | This is COOL! Thanks a lot! I was thinking about using conditional probability and a pivotal quantity afterwards to arrive at a CI. I think the result matches what you had in the first part. I never thought about the second part that we can get exact confidence region for $(a,b)$ jointly. Good job! | |
| Aug 15, 2017 at 16:09 | comment | added | Iosif Pinelis | I have provided details on the calculation of $p(c)$. | |
| Aug 15, 2017 at 15:35 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
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| Aug 15, 2017 at 2:34 | comment | added | Iosif Pinelis | @MattF. : There was indeed a typo in the second line of the two-line display. It is now fixed. The ultimate expression for $\alpha$ is, anyway, correct. | |
| Aug 15, 2017 at 2:30 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
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| Aug 15, 2017 at 1:10 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
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| Aug 15, 2017 at 0:22 | comment | added | user44143 | Is the calculus correct in the last step of the big equation? | |
| Aug 15, 2017 at 0:00 | history | edited | user44143 | CC BY-SA 3.0 |
Changed notation for readability
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| Aug 14, 2017 at 21:51 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
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| Aug 14, 2017 at 20:40 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
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| Aug 14, 2017 at 18:34 | history | answered | Iosif Pinelis | CC BY-SA 3.0 |