Assume that $P\in \mathbb{C}[z]$ is a polynomial of degree $n$ with $n$ distinct roots $z_1,z_2,\ldots,z_n$.
We identify $\mathbb{R}^3$ with $\mathbb{C}\times \mathbb{R}$. Put $a_i=(z_i,0)$.
Then $\mathbb{R}^3 \setminus \{a_1,a_2,\ldots,a_n\}$ is the union of $\mathbb{R}^{3\geq0} \setminus \{a_1,a_2,\ldots,a_n\} $ and $\mathbb{R}^{3\leq0} \setminus \{a_1,a_2,\ldots,a_n\} $ where $\mathbb{R}^{3\geq0}=\mathbb{C} \times [0, +\infty)$ and $\mathbb{R}^{3\leq0}=\mathbb{C} \times (-\infty, 0]$.
This enable us to define a complex line bundle on $\mathbb{R}^3 \setminus \{a_1,a_2,\ldots,a_n\}$ using clutching function $1/P(z)$.
Since the wedge sum of $n$, $2\_$ spheres$S^2$ is a deformation retract of $\mathbb{R}^3 \setminus \{a_1,a_2,\ldots,a_n\}$, we get a line bundle on the wedge sum of the spheres.
Does the isometric class of this line bundle depend on choosing initial polynomial $P(z)$? What is the explicit formulation of the (first) Chern class of this line bundle, in $\oplus_{i=1}^n \mathbb{Z}$, the cohomology of the base space?( In terms of the coefficients of $P(z)$)