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Jul 13, 2018 at 14:48 comment added Tim Carson Actually now I don't remember why I said rational-valued. It seems like any function $p : \{0, 1, ..., 9\} \to \mathbb{R}$ would do.
Jun 26, 2018 at 19:22 comment added Anthony @TimCarson I finally understand what you mean by "any rational-valued function. " I understand now.
Aug 22, 2017 at 19:13 history edited Anthony CC BY-SA 3.0
Error pointed about by commentator. Rewritten to correct.
Aug 22, 2017 at 19:05 comment added Tim Carson As written the sum is infinite. If you fix it (to what's written in the stack exchange post) I would argue that this is unsurprising. You could replace $p$ with any rational-valued function and it would still be true with constant $(p(0) + p(1) + \cdots + p(9))/(0 + 1 + \cdots + 9)$.
Aug 22, 2017 at 11:57 history edited Anthony CC BY-SA 3.0
Added a graph.
S Aug 11, 2017 at 15:25 history answered Anthony CC BY-SA 3.0
S Aug 11, 2017 at 15:25 history made wiki Post Made Community Wiki by Anthony