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Aug 10, 2017 at 12:07 comment added Jon Pridham On the other hand, the enumerated procedure you describe with multiple variables looks like the universal deformation over the hull of the deformation functor.
Aug 10, 2017 at 11:48 comment added José Figueroa-O'Farrill Hi @JonPridham. Indeed. My rephrasing needs work. In your example, if a nontrivial bracket is divisible by $t^2$ then the first nonzero term is still a cocycle, so then the question is whether if the $t^2$ term is a coboundary, whether the deformation is trivial. I need to think more about this, because I'm starting to think that the answer is negative.
Aug 10, 2017 at 9:03 comment added Jon Pridham Can't you get a counterexample to the rephrased question by starting from an abelian Lie algebra, taking $\alpha_1=0$ and $\alpha_2$ to be any non-trivial bracket divisible by $t^2$?
Aug 10, 2017 at 8:03 comment added José Figueroa-O'Farrill I'm interested in whole deformations: so solutions of the Maurer-Cartan equation modulo gauge transformations. However, for lack of a better way, I'm solving the equation perturbatively. I have added more information to the question to clarify.
Aug 10, 2017 at 8:03 history edited José Figueroa-O'Farrill CC BY-SA 3.0
added a rephrasing of the original question to clarify after a comment.
Aug 10, 2017 at 2:16 comment added user40276 I don't know if I've understood the question, but it's a general fact that any deformation problem is given by the Maurer-Cartan elements of a DGLA (the infinitesimal automorphisms of the functor defining the problem) modulo gauge transformations. The Maurer-Cartan equation says that you can extend the problem to a higher order deformation, while the gauge transformation takes into account this irrelevance given by these cocycles representing the same cohomology class. Now I couldn't really understand whether you're only picking first-order deformations or if you want the whole deformation.
Aug 9, 2017 at 17:48 history asked José Figueroa-O'Farrill CC BY-SA 3.0