Timeline for Finding the asymptotic bound of a summation
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Aug 10, 2017 at 8:04 | history | edited | Brendan McKay | CC BY-SA 3.0 |
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| Aug 10, 2017 at 8:00 | comment | added | Brendan McKay | @ChristianRemling $i^3/n^2$ can be around a constant in the later part of the first range but there it is overwhelmed by the term $-i^2/(2n)$ and has negligible effect. However the argument might be clearer if the cut is made between $n^{1/2}$ and $n^{2/3}; I'll edit it like that. | |
| Aug 9, 2017 at 22:04 | comment | added | Christian Remling | Thanks. I still think you're not establishing the precise constant $\sqrt{\pi/2}$ with your theoretical argument since the $e^{O(i^3/n^2)}=e^{O(1)}$ can contribute to this. | |
| Aug 9, 2017 at 21:45 | history | edited | Brendan McKay | CC BY-SA 3.0 |
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| Aug 9, 2017 at 21:31 | comment | added | Brendan McKay | @ChristianRemling Yes, I was careless. Fixing now. | |
| Aug 9, 2017 at 9:51 | history | answered | Brendan McKay | CC BY-SA 3.0 |