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Mar 19, 2018 at 6:57 comment added David Roberts Using $\mathbb{E}(G,H)$ one could expect to get a group rather than a ring, assuming $H$ is abelian. If $H$ is not abelian then perhaps the groupoid structure is still interesting. In any case, the construction looks very much like some kind of cohomology. Given $\mathbb{E}(G)$ as you have defined it, I'm not sure that for nonabelian $G$ you'll get a group.
Mar 19, 2018 at 6:54 history edited David Roberts CC BY-SA 3.0
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Aug 8, 2017 at 2:10 history asked Alex Meiburg CC BY-SA 3.0