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Aug 4, 2017 at 16:24 vote accept lsn
Aug 4, 2017 at 2:30 history edited Henry.L CC BY-SA 3.0
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Aug 4, 2017 at 2:25 comment added Henry.L @lsn_rice No, the Hilbert structure is lost and we need more consideration.
Aug 4, 2017 at 2:25 comment added lsn What if x,y are not L^2? This still works?
Aug 4, 2017 at 2:24 comment added Henry.L @lsn_rice That lattice is distributive under scalar and vector addition.
Aug 4, 2017 at 2:22 comment added lsn What is a lattice that is compatible with $H$?
Aug 4, 2017 at 2:21 history answered Henry.L CC BY-SA 3.0