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Aug 17, 2017 at 2:23 vote accept Jingren Chi
Aug 15, 2017 at 8:45 answer added David Rydh timeline score: 5
Jul 31, 2017 at 18:04 history edited Jingren Chi CC BY-SA 3.0
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Jul 29, 2017 at 2:03 history edited Jingren Chi CC BY-SA 3.0
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Jul 28, 2017 at 20:08 comment added Niels @HCCH : if $k$ is algebraically closed, the étale topos of $BG$ is $G$-Sets, so it is not equivalent to the étale topos of $spec (k)$, which is Sets. So considering the topoi doesn't help.
Jul 28, 2017 at 19:15 history edited Jingren Chi CC BY-SA 3.0
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Jul 28, 2017 at 16:34 comment added Jason Starr Objects in the etale site of $BG$ can have more automorphisms than the corresponding objects of the etale site of $\text{Spec}(k)$.
Jul 28, 2017 at 15:00 comment added Jingren Chi @Niels: I'm also confused by this. What about their etale topos? I guess in general inequivalent sites could give rise to equivalent topos?
Jul 28, 2017 at 7:42 comment added Niels Something is wrong with your analysis in Question 2. For instance it is clear that if $G$ acts trivially on $A=k$ a field, then $BG$ and $spec(k)$ don't have equivalent étale sites.
Jul 28, 2017 at 4:33 history asked Jingren Chi CC BY-SA 3.0