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Jul 26, 2017 at 16:34 vote accept Math_Y
Jul 26, 2017 at 16:34
Jul 26, 2017 at 16:02 comment added David Harris Also, this bound is tight. Suppose $X$ and $Y$ are $-1, +1$ with probability $1/2$. Then $|X+Y| = 2$ with probability $1/2$ and $0$ otherwise, while $|X| = |Y| = 1$.
Jul 26, 2017 at 15:56 history answered Aleksei Kulikov CC BY-SA 3.0