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Aug 2, 2017 at 7:51 answer added M.González timeline score: 5
S Jul 26, 2017 at 8:05 history suggested Martin Sleziak
added (stone-cech) tag
Jul 26, 2017 at 7:51 comment added Martin Sleziak This seems related: Why is $\beta(\mathbb{N}\times\mathbb{N})\neq\beta(\mathbb{N})\times\beta(\mathbb{N})$? (math.SE)
Jul 26, 2017 at 7:47 review Suggested edits
S Jul 26, 2017 at 8:05
Jul 26, 2017 at 6:04 answer added მამუკა ჯიბლაძე timeline score: 14
Jul 25, 2017 at 22:35 answer added YCor timeline score: 11
Jul 25, 2017 at 20:48 comment added Todd Trimble I don't have the leisure at the moment to develop this, but I'd be tempted to work on the other side of Stone duality. $\beta N$ is the Stone space of the Boolean ring $P N$ and $\beta N \times \beta N$ is the Stone space of the tensor product of commutative rings $P N \otimes P N$. My thinking is to show the latter can't possibly be complete as a Boolean algebra.
Jul 25, 2017 at 20:06 comment added Qfwfq @Asaf: okay: done.
Jul 25, 2017 at 20:06 history edited Qfwfq CC BY-SA 3.0
added 49 characters in body
Jul 25, 2017 at 19:59 comment added Asaf Karagila @Qfwfq: If you're fixin' the title, might as well fix the body also...
Jul 25, 2017 at 19:51 history edited Qfwfq CC BY-SA 3.0
made title more informative
Jul 25, 2017 at 19:46 answer added Taras Banakh timeline score: 17
Jul 25, 2017 at 19:34 comment added MathsAlppila I appreciate it Taras...in any case I would like to know a map if it exists...
Jul 25, 2017 at 19:32 comment added Taras Banakh Instead of putting negative marks better write an answer. Otherwise this will be a discouraging experience for MathsAlppila. The question seems to be reasonable and not entirely trivial.
Jul 25, 2017 at 19:23 review First posts
Jul 25, 2017 at 21:19
Jul 25, 2017 at 19:18 history asked MathsAlppila CC BY-SA 3.0