Timeline for Is there a matrix with this specific quadratic determinant?
Current License: CC BY-SA 3.0
23 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Oct 31, 2018 at 16:20 | review | Close votes | |||
Nov 6, 2018 at 20:35 | |||||
Aug 6, 2017 at 5:49 | review | Close votes | |||
Aug 6, 2017 at 12:37 | |||||
Aug 6, 2017 at 4:12 | history | edited | Turbo | CC BY-SA 3.0 |
added 813 characters in body
|
Aug 2, 2017 at 13:26 | comment | added | Abdelmalek Abdesselam | Did you look at arxiv.org/abs/1508.05788 ? They might have a method for answering your question. | |
Aug 2, 2017 at 11:05 | review | Suggested edits | |||
Aug 2, 2017 at 11:27 | |||||
S Aug 2, 2017 at 10:52 | history | suggested | Amir Sagiv | CC BY-SA 3.0 |
added a relevant tag + title more informative
|
Aug 2, 2017 at 10:51 | review | Suggested edits | |||
S Aug 2, 2017 at 10:52 | |||||
Aug 2, 2017 at 10:39 | history | reopened |
Steven Landsburg Wolfgang Alexey Ustinov Stefan Kohl♦ Francois Ziegler |
||
Aug 2, 2017 at 9:32 | history | edited | Stefan Kohl♦ |
edited tags
|
|
Aug 2, 2017 at 3:02 | review | Reopen votes | |||
Aug 2, 2017 at 10:39 | |||||
Jul 25, 2017 at 7:39 | comment | added | Turbo | @StevenLandsburg I think if I am right any polynomial can be expressed as determinant (and the size is the central issue as in permanent determinant case) and so $det(M)+det(N)$ should be representable as a determinant. | |
Jul 25, 2017 at 4:16 | comment | added | Steven Landsburg | The more general question is: Given matrices $M$ and $N$, when does there exist a matrix $P$ all of whose entries appear in $M$ and $N$ and such that $det(P)=det(M)+det(N)$ ? Can you settle any non-trivial cases of this? | |
Jul 25, 2017 at 4:09 | comment | added | Christian Remling | I actually suspect this is not possible, but I don't know how to prove that. It seems an interesting question to me, but maybe I missed something. I voted to reopen. | |
Jul 25, 2017 at 1:17 | comment | added | Turbo | @YemonChoi I think it has to be larger. I think it has be be somewhere between linear and quadratically as large as the number of summations needed. | |
Jul 24, 2017 at 20:35 | comment | added | Yemon Choi | I didn't vote to close, so this is an honest question: do you require A to also be a 4 by 4 matrix, or can it be larger? | |
Jul 24, 2017 at 18:11 | history | edited | Christian Remling | CC BY-SA 3.0 |
added 22 characters in body
|
Jul 24, 2017 at 17:07 | review | Reopen votes | |||
Jul 24, 2017 at 20:04 | |||||
Jul 24, 2017 at 16:41 | history | undeleted | user106049 | ||
Jul 24, 2017 at 16:40 | history | deleted | user106049 | via Vote | |
Jul 24, 2017 at 9:10 | comment | added | Turbo | The query came from understanding formula complexity. Don't understand the meaning of this ridicule. | |
Jul 24, 2017 at 5:40 | history | closed |
Andreas Blass Will Jagy user6976 abx Stefan Waldmann |
Not suitable for this site | |
Jul 24, 2017 at 2:06 | review | Close votes | |||
Jul 24, 2017 at 5:40 | |||||
Jul 24, 2017 at 1:27 | history | asked | Turbo | CC BY-SA 3.0 |