Skip to main content

Timeline for Definition of $S_1(A,B)$

Current License: CC BY-SA 3.0

6 events
when toggle format what by license comment
Jul 23, 2017 at 10:56 comment added Boaz Tsaban @AlexanderOsipov Yes, this holds for all of the Scheepers diagram, and also in the Borel case. Same proofs work.
Jul 23, 2017 at 10:54 comment added Boaz Tsaban @AlexanderOsipov Yes, the proof for $S_1(\Omega,\Gamma)$ is the same. Indeed, in courses I prove for $S_1(\Gamma,\Gamma)$ and then deduce for $S_1(\Omega,\Gamma)$ as an immediate consequence.
Jul 23, 2017 at 6:58 vote accept Alexander Osipov
Jul 23, 2017 at 6:54 comment added Alexander Osipov If I understood correctly, then this is true for any principle in The Scheepers Diagram ( Including the Borel covers ) ?
Jul 23, 2017 at 6:48 comment added Alexander Osipov Thanks! I was more interested the principle $S_1(\Omega, \Gamma)$, but i find Gerlits-Nagy's result that $S_1(\Omega, \Gamma)={ \Omega\choose \Gamma}$.
Jul 22, 2017 at 22:05 history answered Boaz Tsaban CC BY-SA 3.0