Timeline for Smooth intertwining operators
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| S Jul 29, 2017 at 9:29 | history | bounty ended | CommunityBot | ||
| S Jul 29, 2017 at 9:29 | history | notice removed | CommunityBot | ||
| Jul 28, 2017 at 10:50 | vote | accept | MathStudent | ||
| Jul 28, 2017 at 10:49 | answer | added | MathStudent | timeline score: 1 | |
| S Jul 21, 2017 at 7:31 | history | bounty started | MathStudent | ||
| S Jul 21, 2017 at 7:31 | history | notice added | MathStudent | Draw attention | |
| Jul 18, 2017 at 15:36 | history | edited | Myshkin | CC BY-SA 3.0 |
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| Jul 18, 2017 at 14:54 | comment | added | MathStudent | I think that the character $\chi=\beta \otimes \alpha|\cdot|^{-1}$ is the tensor product of two unramified characters (see equation 24 and equation 25 in page 38 of the pdf "math.u-psud.fr/~breuil/PUBLICATIONS/Hangzhou.pdf". By Iwasawa decomposition $Ind_{B(\mathbb{Q}_p)}^{G(\mathbb{Q}_p)}(\chi)\cong Ind_{B(\mathbb{Z}_p)}^{G(\mathbb{Z}_p)}(\chi)$ and since $\chi $ is the tensor product of two unramified characters $\chi$ is trivial on $B(\mathbb{Z}_p)$ which implies (as a vector space) $Ind_{B(\mathbb{Q}_p)}^{G(\mathbb{Q}_p)}(\chi) \cong Ind_{B(\mathbb{Z}_p)}^{G(\mathbb{Z}_p)}(1)$ | |
| Jul 18, 2017 at 14:02 | comment | added | user94041 | What do you mean by $h=1$? Unless you are assuming that $\beta$ is trivial and $\alpha = | \cdot |$, I do not see how the constant function on $G$ with value $1$ could belong to $Ind^G_B \left( \beta \otimes \alpha | \cdot |^{-1} \right)^{sm}$. | |
| Jul 18, 2017 at 11:11 | history | asked | MathStudent | CC BY-SA 3.0 |