For positive integers n$n$ and L$L$, denote by SL_n(Z,L)$SL_n(Z,L)$ the level L$L$ congruence subgroup of SL_n(Z)$SL_n(Z)$, iei.e. the kernel of the homomorphism SL_n(Z)-->SL_n(Z/LZ)$SL_n(Z)\rightarrow SL_n(Z/LZ)$.
For n$n$ at least 3$3$, it is known that SL_n(Z,L)$SL_n(Z,L)$ is normally generated (as a subgroup of SL_n(Z)$SL_n(Z)$) by Lth powers of elementary matrices. Indeed, this is essentially equivalent to the congruence subgroup problem for SL_n(Z)$SL_n(Z)$.
However, this fails for SL_2(Z,L)$SL_2(Z,L)$ since SL_2(Z)$SL_2(Z)$ does not have the congruence subgroup property.
Question : Is there a nice generating set for SL_2(Z,L)?$SL_2(Z,L)\ ?$ I'm sure this is in the literature somewhere, but I have not been able to find it.