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Jul 21, 2017 at 2:26 comment added Hugh Thomas If $n$ is at least 2, then the coefficient of $w_1$ should be 2.
Jul 20, 2017 at 23:18 comment added Max Flander @HughThomas ah i see your point, i've edited the formula again
Jul 20, 2017 at 23:18 history edited Max Flander CC BY-SA 3.0
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Jul 20, 2017 at 14:49 comment added Hugh Thomas I still disagree with what you've written: shouldn't the coefficient of $w_1$ be 2, once for position 1 and once for position $n$?
Jul 20, 2017 at 3:42 history edited Max Flander CC BY-SA 3.0
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Jul 20, 2017 at 3:42 comment added Max Flander @HughThomas yes you're right, thanks for this, i've fixed the indices
Jul 19, 2017 at 9:43 comment added Hugh Thomas I don't think your formula for the distance between the identity and the longest permutation is correct. $w_n$ shouldn't appear at all, and, unless I'm misunderstanding, $w_1$ would appear twice, once for position 1, and once for position $n$.
Jul 19, 2017 at 5:12 history edited Max Flander CC BY-SA 3.0
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Jul 18, 2017 at 23:44 comment added Max Flander @RW i've added the reference (apologies if i'm abusing the term)
Jul 18, 2017 at 23:43 history edited Max Flander CC BY-SA 3.0
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Jul 18, 2017 at 23:40 comment added Max Flander @DirkLiebhold yes that's what i mean, i've edited the question
Jul 18, 2017 at 12:23 comment added R W Are you talking just about just the usual graph metric on the Cayley graph of the symmetric group with respect to the generating set which consists of permutations with weighted lengths? It has nothing to do with any "earth-moving" (which only arises when one talks about distances between measures).
Jul 18, 2017 at 9:19 comment added Dirk Can you give a formal definition of the term "weighted earth-mover's distance between permutations". And what is a "transposition at position $i$?" Do you mean the transposition $(i,i+1)$?
Jul 18, 2017 at 4:53 history asked Max Flander CC BY-SA 3.0