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Oct 23, 2017 at 13:08 history edited Dominic van der Zypen CC BY-SA 3.0
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Jul 25, 2017 at 20:31 comment added Mathieu Baillif Haha, of course. When I wrote my remark I somehow forgot that the union of two nowhere dense sets is nowhere dense.
Jul 25, 2017 at 11:52 comment added Ramiro de la Vega @MathieuBaillif Note that $v(X)=cov(X)$ except for meager spaces where $v(X)=\aleph_0$ and $Cov(X)=1$.
Jul 25, 2017 at 11:49 comment added Wlod AA (@RamirodelaVega, I was joking. Sorry. PS. Ok, Taras has answered the question fully in his comment to this question and to the follow up question).
Jul 25, 2017 at 11:46 comment added Ramiro de la Vega I don't think your older question is asking what you claim it is. Any space has $v(X)>2$.
Jul 25, 2017 at 11:29 comment added Wlod AA What about $\ \kappa=2\ $ ?
Jul 17, 2017 at 15:15 comment added Mathieu Baillif This is just a remark: if instead of nowhere dense sets we consider coverings by meager sets, we obtain the classical covering number of $X$, usually written as Cov$(X)$. But you are probably aware of that.
Jul 15, 2017 at 14:04 history asked Dominic van der Zypen CC BY-SA 3.0