Timeline for Compact operators on $\ell^1$
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jul 14, 2017 at 21:11 | vote | accept | BaoLing | ||
Jul 14, 2017 at 21:07 | comment | added | Yemon Choi | Regarding your edit, I think the problem is that the spectral containment you mention doesn't really say anything about the multiplicity of points in the spectrum. So the points which are non-zero eigenvalues for your compact operator on $\ell^2$ might still be eigenvalues for the operator on $\ell^1$, but with "infinite multiplicity" now. | |
Jul 14, 2017 at 16:33 | comment | added | Bill Johnson | To get an example it is enough to observe that you can find vectors $x$ in $\ell_1$ s.t. the ratio of $\|x\|_1 \cdot \|x\|_\infty $ to $\|x\|_2^2$ is arbitrarily large. Consider, for example, $x_n :=n^{1/2} e_1 + \sum_{k=2}^n e_k$; the desired ratio is about $n^{1/2}$. Take $\sum_{n\in S} n^{-3/2} x_n\otimes x_n$ where the $S$ is infinite, $\sum_{n\in S} n^{-1/2} < \infty$, and the sum is a direct sum. | |
Jul 14, 2017 at 14:47 | history | edited | BaoLing | CC BY-SA 3.0 |
added 665 characters in body
|
Jul 14, 2017 at 12:53 | answer | added | Matthew Daws | timeline score: 5 | |
Jul 14, 2017 at 8:05 | history | edited | BaoLing | CC BY-SA 3.0 |
added 199 characters in body
|
Jul 13, 2017 at 20:37 | history | edited | BaoLing | CC BY-SA 3.0 |
added 41 characters in body
|
Jul 13, 2017 at 20:25 | history | asked | BaoLing | CC BY-SA 3.0 |