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Nov 29, 2013 at 14:46 comment added Olivier Benoist I also believe that the answer is not correct as it stands : one should not be able to reconstruct a vector bundle from its endomorphism bundle.
Oct 12, 2013 at 11:28 comment added Martin Brandenburg At which section(s)? Locally it is a localization, but not globally.
Oct 12, 2013 at 10:15 comment added S. Carnahan @MartinBrandenburg I'm pretty sure it is a localization of $\mathcal{O}_Y$-algebras.
Oct 12, 2013 at 8:25 comment added Martin Brandenburg But still this cannot work, since for $n=1$ say $\oplus_{d \in \mathbb{Z}} V^{\otimes d}$ is not a localization of $\oplus_{d \in \mathbb{N}} V^{\otimes d}$.
Oct 11, 2013 at 16:34 comment added Martin Brandenburg This cannot be true. If $n=1$, then $R = \oplus_{n \in \mathbb{Z}} V^{\otimes n}$. However, your algebra is $\mathcal{O}[T,T^{-1}]$, which doesn't depend on $V$. I think instead of $\underline{\mathrm{End}}(V) = V^* \otimes V$, we have to consider $\underline{\mathrm{Hom}}(\mathcal{O}^n,V) \cong V^n$, as in Mattia's answer.
Jun 9, 2010 at 15:36 comment added S. Carnahan This clears up a lot. I think the jet bundles come from an associated bundle construction using automorphism groups of infinitesimal neighborhoods, so first order uses $GL_n$, but higher order uses nilpotent extensions by $1 + M_n[t]/t^k$.
Jun 9, 2010 at 7:36 comment added Michael Thaddeus My understanding is that the 1-jets lie in an extension 0 --> T* --> J(1) --> O --> 0, which is split by the functions vanishing at the given point and the constant functions. So J(1) = T* + O. On the other hand, the extensions defining higher jets 0 --> Sym^k T* --> J(k) --> J(k+1) --> 0 need not split. Since representations of GL(n) are completely reducible, this means you won't obtain the jet bundles from any associated bundle construction starting from the tangent bundle.
Jun 9, 2010 at 1:19 comment added S. Carnahan Thank you, Michael. Now I think I have mixed up two constructions, and that the torsor P with the associated bundle property I wanted is not the same as the adjoint $GL_n$-bundle of automorphisms. Is that the case?
Jun 8, 2010 at 23:16 history answered Michael Thaddeus CC BY-SA 2.5