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Jul 10, 2017 at 11:06 comment added Wenzhe Thank you very much for your answer, this is really helpful.
Jul 10, 2017 at 10:53 comment added François Brunault Yes, you're right, thanks for pointing it out. I've not been very careful about the signs.
Jul 10, 2017 at 10:52 history edited François Brunault CC BY-SA 3.0
corrected $\det(\alpha) \to \det(\alpha)^{-1}$
Jul 10, 2017 at 9:56 comment added Wenzhe In the second last sentence of the first paragraph, shoud $\text{det}(\alpha)k_0$ be $\text{det}(\alpha)^{-1}k_0$?
Jul 10, 2017 at 7:45 vote accept Wenzhe
Jul 10, 2017 at 7:05 history answered François Brunault CC BY-SA 3.0