Timeline for What function is this? -Counterexample found: it is not Lipschitz-

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Jul 13, 2017 at 15:00	comment	added	Pietro Majer		Right, I meant that for a continuous $p$, and I should have added: for any $0\le s \le t\le1$ such that $\theta(s)\neq \theta(s)$ (edited). In this case the existence of $s\le s'\le t'\le t$ as required is OK (and it is sufficient to conclude). There are of course other statements that do; yours seems simpler and more general.
Jul 13, 2017 at 14:57	history	edited	Pietro Majer	CC BY-SA 3.0	added 32 characters in body
Jul 12, 2017 at 8:06	comment	added	Dirk		Did you mean that there exist $s',t'$ with $0\leq s'\leq t\leq t'\leq 1$ such that $p(t') = \theta(t)$ and $p(s') = \theta(s)$. Otherwise I don't see how these $s'$ and $t'$ should exist, and also this gives the right estimate $(\theta(t)-\theta(s))/(t-s) = (p(t')-p(s'))(t-s) \leq (p(t')-p(s'))/(t'-s')$.
S Jul 11, 2017 at 12:47	history	suggested	Joe	CC BY-SA 3.0	Changed function name
Jul 11, 2017 at 12:40	review	Suggested edits
S Jul 11, 2017 at 12:47
Jul 9, 2017 at 14:06	history	edited	Pietro Majer	CC BY-SA 3.0	added 196 characters in body
Jul 9, 2017 at 8:00	history	edited	Pietro Majer	CC BY-SA 3.0	added 232 characters in body
Jul 9, 2017 at 7:34	history	edited	Pietro Majer	CC BY-SA 3.0	deleted 23 characters in body
Jul 9, 2017 at 7:28	history	answered	Pietro Majer	CC BY-SA 3.0