Timeline for What kind of line bundles have Chern class of Hodge type (2,0) or (0,2)?
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| Jun 8, 2010 at 21:38 | answer | added | Tim Perutz | timeline score: 3 | |
| Jun 8, 2010 at 20:03 | history | edited | David Treumann | CC BY-SA 2.5 |
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| Jun 8, 2010 at 19:22 | answer | added | Donu Arapura | timeline score: 3 | |
| Jun 8, 2010 at 19:18 | comment | added | Tim Perutz | Um... Assume $X$ is Kaehler so that I have a Hodge decomposition. Doesn't complex conjugation then map $H^{(2,0)}$ into $H^{(0,2)}$? So isn't it the case that the image of $H^2(X;\mathbb{Z})$ in $H^2(X;\mathbb{C})$ intersects the $(2,0)$ part trivially? (One could ask about the real part of $H^{(2,0)}+H^{(0,2)}$, though.) | |
| Jun 8, 2010 at 19:05 | history | asked | David Treumann | CC BY-SA 2.5 |