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Jun 11, 2010 at 12:33 vote accept Ian Morris
Jun 11, 2010 at 12:33 comment added Ian Morris Agol: thank you for this excellent and very useful extended answer!
Jun 10, 2010 at 19:54 history edited Ian Agol CC BY-SA 2.5
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Jun 10, 2010 at 0:33 comment added Ben Wieland Qiaochu's examples don't commute. Also, he might as well take the square root of C, [[1,1][1,2]].
Jun 9, 2010 at 23:25 comment added Ian Agol @Qiaochu: Did you check that your pairs of matrices are nonconjugate? Remember, there is a 1-parameter family of matrices commuting with C. I think you've found a parametrization of the matrices obtained by conjugating B by this family (although I didn't check your formulae).
Jun 8, 2010 at 17:42 comment added Qiaochu Yuan I think the statement is false in SL_2(C); in the setup in my comment above one can take k = l = 1, C = [[2 3][3 5]], X = 0, and Y = [[b+c b][c -b-c]] where b^2+3bc+c^2 = 0.
Jun 8, 2010 at 17:41 history edited Ian Agol CC BY-SA 2.5
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Jun 8, 2010 at 17:35 history undeleted Ian Agol
Jun 8, 2010 at 17:21 history deleted Ian Agol
Jun 8, 2010 at 17:00 comment added Ian Morris Thanks! Could you provide a reference for the general result which you use here (or a name or keyword, so I can look it up myself)?
Jun 8, 2010 at 16:53 history answered Ian Agol CC BY-SA 2.5