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Dec 14, 2011 at 11:06 comment added Ian Morris Ian Agol's answer has been incorporated into the article "On a Devil’s staircase associated to the joint spectral radii of a family of pairs of matrices" which will be published in Journal of the European Mathematical Society in late 2012.
Jun 11, 2010 at 12:33 vote accept Ian Morris
Jun 8, 2010 at 16:53 answer added Ian Agol timeline score: 10
Jun 8, 2010 at 16:00 comment added Qiaochu Yuan Some thoughts. I believe the second condition requires that tr A = tr C^k and tr B = tr C^l for some C in SL(2, Z). If we then write A = C^k + X, B = C^l + Y where X, Y are traceless, the first condition is equivalent to the statement that X C^l + C^k Y + XY has trace zero. I think I can show this is impossible if X = 0.
Jun 8, 2010 at 14:45 history asked Ian Morris CC BY-SA 2.5