The answer is nono. Start with $\alpha$ between 3.25 and 3.75; take squares of those 2 to see that one can restrict $\alpha^2$ to being between 11.25 and 11.75; take 3/2 powers of those to see that one can restrict $\alpha^3$ to being between 38.25 and 38.75; take 4/3 powers of those etc. One gets the idea and it's very easy: since $\alpha>3$ a 0.5 wide interval is magnified to prove allan interval of width >1.5 by moving to the details rigorouslynext power. Such interval can always be narrowed to $[n+0.25,n+0.75]$ for some integer $n$.