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Aug 9, 2017 at 17:36 comment added Yoav Kallus The down voter was I (now reversed). Thanks for the explanation, which explains what your approximation is trying to optimize. Note that the OP asked about approximation for $x>8.2$, for which your approximation, while OK in terms of absolute difference between the actual value and the approximation, is bad in terms of relative difference.
Aug 9, 2017 at 16:52 comment added Alt I needed a fast way of computing the normal CDF, and the similarity in the shape of this function and the sigmoid function ($\sigma(t) = \frac{1}{1+e^{-t}}$) attracted my attentions. Then, I ran a computer simulation to tune the coefficient $a$ such that $\int_{x1}^{x2}\|\Phi(x)-\sigma(at) \|_2^2dx$ is minimized for some large magnitude negative $x_1$ and positive $x_2$. $a$ turned out to be $−1.65451$.
Aug 9, 2017 at 16:19 comment added Igor Rivin It certainly is not mine, but I am guessing the downvoter was frustrated to not know where this expression came from.
Aug 9, 2017 at 16:02 history edited Alt CC BY-SA 3.0
deleted 33 characters in body
Aug 4, 2017 at 1:50 comment added Alt What is the downvote for?
Jul 5, 2017 at 19:59 review Low quality posts
Jul 5, 2017 at 21:36
Jul 5, 2017 at 17:03 history answered Alt CC BY-SA 3.0