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S Jul 7, 2017 at 19:59 history suggested Luc Guyot CC BY-SA 3.0
If $n$ can be zero, the answer is trivially "yes"
Jul 7, 2017 at 19:44 review Suggested edits
S Jul 7, 2017 at 19:59
Jul 7, 2017 at 10:46 comment added Yaakov Baruch @GerryMyerson: ah - the key is whether the word "always" in the question refers to $\epsilon$, or to both $\alpha$ and $\epsilon$...
Jul 5, 2017 at 22:50 comment added Gerry Myerson Yaakov says the answer is no, Luc says the answer is yes, and they're both right.
Jul 5, 2017 at 20:03 answer added Yaakov Baruch timeline score: 11
Jul 5, 2017 at 17:30 answer added Luc Guyot timeline score: 5
Jul 5, 2017 at 5:23 comment added Gerry Myerson Yes, Igor, but any nontrivial information about the fractional part of $(3/2)^n$ seems to be hard to come by. Mahler proved $\|(3/2)^k\|>(3/4)^k$ for $k$ sufficiently large, where $\|x\|$ is the distance from $x$ to the nearest integer (I realize this doesn't speak to your question, it's just an example of the kind of thing that is known). Habsieger, Acta Arith. 106 (2003), no. 3, 299–309, has $\|(3/2)^k\|>.57434^k$ for $k\ge5$.
Jul 5, 2017 at 4:41 comment added Noam D. Elkies . . . and if it's a Salem number then $\|\alpha^n\|$ has a known distribution and does get arbitrarily (albeit not exponentially) small. en.wikipedia.org/wiki/Salem_number
Jul 5, 2017 at 1:25 comment added Robert Israel Slightly more generally than for the golden ratio, if $\alpha$ is a Pisot-Vijayaraghavan number, $\|\alpha^n \| = \inf_{m \in \mathbb N} |\alpha^n - m| \to 0$ exponentially as $n \to \infty$.
Jul 5, 2017 at 0:36 comment added Igor Rivin @GerryMyerson Some would argue that the question I ask is somewhat easier than the question of distribution.
Jul 4, 2017 at 23:34 comment added Gerry Myerson @René, the question of the distribution of the fractional parts of powers of $3/2$ is a notorious open problem, related to Waring's problem. See, e.g., en.wikipedia.org/wiki/Waring%27s_problem
Jul 4, 2017 at 23:09 comment added R.P. I have trouble answering this even for $\alpha=3/2$...
Jul 4, 2017 at 22:03 comment added Noam D. Elkies True for the golden ratio, at any rate. But that's unusual because for large $n$ every $\alpha^n$ is close to an integer.
S Jul 4, 2017 at 21:52 history suggested jeq CC BY-SA 3.0
Removed stray opening parenthesis.
Jul 4, 2017 at 21:51 review Suggested edits
S Jul 4, 2017 at 21:52
Jul 4, 2017 at 21:28 history asked Igor Rivin CC BY-SA 3.0