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Mikhail Katz
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In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) of a hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

As mentioned for this definable model ACC proves transfer so transfer can't fail in ZF+ACC.

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

As mentioned for this definable model ACC proves transfer so transfer can't fail in ZF+ACC.

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) of a hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

As mentioned for this definable model ACC proves transfer so transfer can't fail in ZF+ACC.

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Mikhail Katz
  • 16.6k
  • 2
  • 54
  • 127

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

As mentioned for this definable model ACC proves transfer so transfer can't fail in ZF+ACC.

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.

As mentioned for this definable model ACC proves transfer so transfer can't fail in ZF+ACC.

Source Link
Mikhail Katz
  • 16.6k
  • 2
  • 54
  • 127

In this arxiv post (to appear in Journal of Symbolic Logic) we prove the existence of an explicitly definable set-theoretic construction in ZF (without if/else clauses) hyperreal extension ${}^\ast\mathbb R$. If in addition countable choice is assumed then we prove that the transfer principle holds for this $^{\ast}\mathbb R$. Assumping the existence of a free ultrafilter on $\mathbb N$ with well-orderable base (an assumption weaker than the well-ordering of $\mathbb R$) we show that the extension $\mathbb {R}\hookrightarrow{}^\ast\mathbb R$ is proper.