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Jul 5, 2017 at 15:22 history closed user6976
Alexey Ustinov
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Jun 30, 2017 at 16:39 review Low quality posts
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Jun 29, 2017 at 20:09 vote accept DaKnOb
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Jun 29, 2017 at 18:54
Jun 29, 2017 at 14:50 comment added Brendan McKay Use a circulant graph: en.wikipedia.org/wiki/Circulant_graph which works for every $\ell,n$ such that $0\le\ell\le n-1$ and $\ell n$ is even. If $\ell n$ is odd, no graph exists.
Jun 29, 2017 at 10:58 answer added Dirk timeline score: 4
Jun 29, 2017 at 10:36 comment added DaKnOb So far I've figured a way to make this work with a given l, but n must be restricted to (multiples of) 2^l. Thanks a lot of the help. Let's wait and see.
Jun 29, 2017 at 10:30 comment added Dirk Possible: Yes, this is a finite problem. However, I don't know of an algorithm to do it, so you either have to wait for someone else to come up with one or design one yourself.
Jun 29, 2017 at 10:21 comment added DaKnOb Is it then possible to generate a graph with such properties? Just any graph. Thanks!
Jun 29, 2017 at 10:20 comment added Dirk Such a graph is not unique, not even up to isomorphism. Thus, it would be hard to find an algorithm to generate "the graph". Take for example two triangles and a circle on six points: In both graphs, you have six points and every point has degree two.
Jun 29, 2017 at 10:07 history edited DaKnOb CC BY-SA 3.0
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Jun 29, 2017 at 9:59 review First posts
Jun 29, 2017 at 10:04
Jun 29, 2017 at 9:56 history asked DaKnOb CC BY-SA 3.0