Skip to main content
3 events
when toggle format what by license comment
Jun 28, 2017 at 17:58 vote accept Thomas Kahle
Jun 27, 2017 at 19:03 comment added Fedor Petrov ah, it is $(z-1)(y-1)(zy-1)=((zy+1)-(z+y))(zy-1)=z^2y^2-1-z^2y-y^2z+z+y$, where $z=x^2$
Jun 27, 2017 at 18:50 history answered Peter Mueller CC BY-SA 3.0