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Jun 26, 2017 at 4:48 comment added Christian Remling In general, minimizing in $\ell^1$ and $\ell^2$ is not the same thing, so it's surprising (to me) that this works so smoothly here. For example, for $d=2$, $n=3$ equally spaced vectors beat the orthogonal configuration for $p=2$.
Jun 26, 2017 at 4:47 comment added Fedor Petrov Alas, $\sum \langle v_i, v_j\rangle^2$ has different minimizer already for $n=3$, $d=2$.
Jun 26, 2017 at 4:30 vote accept TOM
Jun 26, 2017 at 4:07 history answered fedja CC BY-SA 3.0