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Jun 24, 2017 at 14:16 comment added Neil Strickland @ViditNanda The absolute value was conjectured by SylvainJULIEN, and easily verified numerically. It is also easily visible numerically that $\Delta(d)=d^{d/2}i_{m_d}$ for some $m_d$ which only matters mod $4$ and which you can tabulate. You then observe that $m_{d+8}=m_{7-d}=m_d\pmod{4}$, and from there you only need a little guesswork.
Jun 23, 2017 at 23:00 comment added GH from MO I confirmed your formula below.
Jun 23, 2017 at 22:51 comment added Vidit Nanda Amazing. Did you use the OEIS, or are the origins of this formula voodoo-theoretic?
Jun 23, 2017 at 19:20 history edited Neil Strickland CC BY-SA 3.0
Replaced table of values of m_d by a formula
Jun 23, 2017 at 19:08 comment added Gerhard Paseman The matrix determinant is equivalent, as Federico mentioned above, to a scalar t times the determinant of a modified Vandermonde with first column all 1's and remaining columns the ijth power of the root of unity. If you can come up with a proof or expression for t(d), you might get a proof of the general result. Gerhard "T For Two Or Three" Paseman, 2017.06.23.
Jun 23, 2017 at 18:10 history answered Neil Strickland CC BY-SA 3.0