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S Oct 23, 2017 at 9:00 history suggested CommunityBot CC BY-SA 3.0
Slightly shortened already-bumped question.
Oct 23, 2017 at 4:54 review Suggested edits
S Oct 23, 2017 at 9:00
Jun 24, 2017 at 17:56 answer added efs timeline score: 8
Jun 24, 2017 at 16:27 answer added T. Amdeberhan timeline score: 5
Jun 24, 2017 at 12:52 vote accept deterroot
Jun 24, 2017 at 12:00 comment added Sylvain JULIEN Thank you very much but there's no magic behind this, it's just a matter a familiarity with numbers.
Jun 24, 2017 at 11:36 comment added Uri Bader This is all very nice, but I am really amazed by how @SylvainJULIEN got his heuristic out of a three experiments datum.
Jun 23, 2017 at 23:00 answer added GH from MO timeline score: 35
S Jun 23, 2017 at 22:28 history suggested Peter Mortensen CC BY-SA 3.0
Copy edited.
Jun 23, 2017 at 21:46 review Suggested edits
S Jun 23, 2017 at 22:28
Jun 23, 2017 at 19:54 answer added Federico Poloni timeline score: 10
Jun 23, 2017 at 18:10 answer added Neil Strickland timeline score: 17
Jun 23, 2017 at 17:38 comment added Sylvain JULIEN Maybe just a coincidence, but still :$ \vert\Delta(2)\vert=2^{2/2} $ , $ \vert\Delta(3)\vert=3^{3/2} $ , $ \vert\Delta(4)\vert=4^{4/2} $ , so you can try to check whether $ \vert\Delta(n)\vert=n^{n/2} $ or not.
Jun 23, 2017 at 16:55 comment added efs I computed the determinant $\Delta(3)$ with a variable $x$ replacing $\xi$ and it can be factorized; it gives $x(x+1)(x-1)^3$. Maybe you can get a simple expression in general, using a Mathematica or any math software.
Jun 23, 2017 at 15:55 review Close votes
Jun 23, 2017 at 21:05
Jun 23, 2017 at 15:39 comment added deterroot That's what I've been trying to do but I didn't succeed. Could you give some more details? Thanks Federico
Jun 23, 2017 at 15:37 comment added Federico Poloni Looks like you can obtain this matrix starting from the Fourier matrix (Vandermonde on roots of unity) and doing a few elementary row operations to subtract the all-ones first row from every other row. This should give you a method to reduce this determinant to the Vandermonde one.
Jun 23, 2017 at 15:32 review First posts
Jun 23, 2017 at 15:34
Jun 23, 2017 at 15:32 history asked deterroot CC BY-SA 3.0