Skip to main content
3 events
when toggle format what by license comment
Jun 22, 2017 at 17:23 comment added Wojowu Since $A$ is strictly lower triangular, $A^n=0$, so $(I-A)^T=I+A+A^2+\dots+A^{n-1}$. This might be a good starting point.
Jun 22, 2017 at 17:02 review First posts
Jun 22, 2017 at 17:05
Jun 22, 2017 at 17:02 history asked user3093264 CC BY-SA 3.0