Timeline for Puiseux's theorem's converse
Current License: CC BY-SA 3.0
6 events
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| Jun 21, 2017 at 18:13 | comment | added | Christian Remling | Elaborating somewhat on abx's comment, the solutions $y$ of $y^n+a_{n-1}(x)y^{n-1} + \ldots + a_0(x) = 0$ are still Puiseux series if the coefficients are only holomorphic (rather than polynomials). | |
| Jun 21, 2017 at 13:01 | comment | added | abx | So, doesn't that give a counter-example to your first question? | |
| Jun 21, 2017 at 9:28 | comment | added | user1337 | @abx I don't think so. | |
| Jun 21, 2017 at 9:19 | comment | added | abx | Do you really think that there exists a polynomial relation $P(x,e^{\frac{1}{x} })=0$? | |
| Jun 21, 2017 at 9:10 | history | asked | user1337 | CC BY-SA 3.0 |