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Jun 19, 2017 at 19:16 vote accept john mangual
Jun 19, 2017 at 18:38 comment added Alexander Chervov Any extended comment on that interesting topic imho would be useful for community
Jun 19, 2017 at 17:27 comment added john mangual why is there both a $\mathbf{T}(\mathbb{Q})$ and also $\mathbf{T}(\mathbb{A})$ ? Is $\mathbb{G}_m$ a functor? what is the group $\mathrm{PG}(B^{(2,\infty)})$ ?
Jun 19, 2017 at 16:37 history answered Denis Chaperon de Lauzières CC BY-SA 3.0