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GH from MO
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The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m+1$ in this theorem, and noting that $\zeta_1(s)$$\xi_1(s)$ equals $s\zeta(s+1)$, the result follows.

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m+1$ in this theorem, and noting that $\zeta_1(s)$ equals $s\zeta(s+1)$, the result follows.

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m+1$ in this theorem, and noting that $\xi_1(s)$ equals $s\zeta(s+1)$, the result follows.

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GH from MO
  • 105.4k
  • 8
  • 294
  • 398

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m$$n=m+1$ in this theorem, and noting that $\zeta_1(s)$ equals $s\zeta(s+1)$, the result follows.

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m$ in this theorem, and noting that $\zeta_1(s)$ equals $s\zeta(s+1)$, the result follows.

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m+1$ in this theorem, and noting that $\zeta_1(s)$ equals $s\zeta(s+1)$, the result follows.

Source Link
GH from MO
  • 105.4k
  • 8
  • 294
  • 398

The identity in Question 1 is a special case of Theorem 2 in Ohno: A Generalization of the Duality and Sum Formulas on the Multiple Zeta Values (see here). Indeed, putting $k=1$ and $n=m$ in this theorem, and noting that $\zeta_1(s)$ equals $s\zeta(s+1)$, the result follows.