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Jul 28, 2017 at 4:28 comment added abx Bourbaki, Commutative Algebra, ch. I, §3, Proposition 12.
S Jul 28, 2017 at 0:03 history suggested Ali Taghavi
I add a tag
Jul 27, 2017 at 23:55 review Suggested edits
S Jul 28, 2017 at 0:03
Jun 15, 2017 at 4:26 comment added Homa81 Thank you very much. But how can I prove this?
Jun 15, 2017 at 4:25 history edited Homa81 CC BY-SA 3.0
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Jun 14, 2017 at 20:30 comment added Mohan If $\Lambda$ is a finitely generated $R$-module, this is correct. If you merely assume that it is just a finitely generated $R$-algebra (as you state in the question), this is false in general.
Jun 14, 2017 at 18:20 comment added Homa81 $\Lambda$ is finitely genreated as an $R$-module. In fact, $\Lambda$ is a noether $R$-algebra.
Jun 14, 2017 at 18:06 comment added Will Sawin Is $\Gamma$ finitely generated as a module or an algebra? If an algebra, what if $R= k[x], \Gamma = k[x,x^{-1}]$?
Jun 14, 2017 at 17:52 review First posts
Jun 14, 2017 at 17:55
Jun 14, 2017 at 17:49 history asked Homa81 CC BY-SA 3.0