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Jun 21, 2017 at 10:04 history edited Ali Taghavi CC BY-SA 3.0
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Jun 13, 2017 at 19:46 vote accept Ali Taghavi
Jun 13, 2017 at 8:24 answer added Robert Bryant timeline score: 10
Jun 13, 2017 at 5:54 comment added Ali Taghavi @alvarezpaiva my apology if my question is elementary. But I do not underestand why the LC conection is automatically Lagrangian. Moreover what is the algebraic formulation of the lagrangian property for the distribution associated with the derivative $\nabla$?
Jun 13, 2017 at 5:47 history undeleted Ali Taghavi
Jun 12, 2017 at 21:56 history deleted Ali Taghavi via Vote
Jun 12, 2017 at 20:47 comment added Ali Taghavi @alvarezpaiva thank you for your comment. What is the reason that the LC connection is lagrangian?what is an algebraic criterion to determine whether a connection $\nabla$ is Lagrangian?
Jun 12, 2017 at 20:41 comment added alvarezpaiva Maybe I'm not understanding your definition, but it seems to me the Levi-Civita connection of any metric Lagrangian. So is the Ehresmann connection associated to any Finsler metric/
Jun 12, 2017 at 20:35 history edited Ali Taghavi CC BY-SA 3.0
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Jun 12, 2017 at 20:27 history asked Ali Taghavi CC BY-SA 3.0