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Ali Taghavi
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Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that for all $z\in TM$, $D_z$ is a lagrangian subspace of $T_z TM$ which is transverse to the vertical foltion of $TM$.

Does every manifold admit a LagrangLagrangian connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that for all $z\in TM$, $D_z$ is a lagrangian subspace of $T_z TM$ which is transverse to the vertical foltion of $TM$.

Does every manifold admit a Lagrang connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that for all $z\in TM$, $D_z$ is a lagrangian subspace of $T_z TM$ which is transverse to the vertical foltion of $TM$.

Does every manifold admit a Lagrangian connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

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Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that for all $z\in TM$, $D_z$ is a lagrangian subspace for allof $z\in TM$$T_z TM$ which is transverse to the vertical foltion of $TM$.

Does every manifold admit a Lagrang connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that $D_z$ is a lagrangian subspace for all $z\in TM$.

Does every manifold admit a Lagrang connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that for all $z\in TM$, $D_z$ is a lagrangian subspace of $T_z TM$ which is transverse to the vertical foltion of $TM$.

Does every manifold admit a Lagrang connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?

Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

A Lagrangian connection and its algebraic interpretation

Assume that $M$ is a $n$ dimensional Riemannian manifold. So $TM$ has a natural structure of a symplectic manifold. A Lagrangian connection $D$ on $M$ is a $n$ dimensional distribution for $TM$ such that $D_z$ is a lagrangian subspace for all $z\in TM$.

Does every manifold admit a Lagrang connection? Is the $LC$ connection necessarily a Lagranģian connection?

Let $\nabla$ be the corresponding derivation associated with a Lagrangian connection.

What formula is satisfied by $\nabla$?