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4 hours ago history edited LSpice CC BY-SA 4.0
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7 hours ago history edited mathoverflowUser
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12 hours ago answer added mathoverflowUser timeline score: 0
Jun 19, 2017 at 2:35 history made wiki Post Made Community Wiki by S. Carnahan
Jun 18, 2017 at 3:03 review Close votes
Jun 19, 2017 at 1:11
Jun 14, 2017 at 7:13 answer added José Hdz. Stgo. timeline score: 2
Jun 12, 2017 at 15:11 history edited T. Amdeberhan CC BY-SA 3.0
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Jun 12, 2017 at 15:05 comment added T. Amdeberhan That is exactly what I meant to say.
Jun 12, 2017 at 15:04 comment added user39297 Do you mean induction that is taken over the primes?
Jun 12, 2017 at 14:58 history edited T. Amdeberhan CC BY-SA 3.0
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Jun 12, 2017 at 9:13 comment added Dirk Are you specifically looking for inductions going from $p_n$ to $p_{n+1}$, or would something like "Assume the statement is true for all $p_i$ with $i \leq n$. Show that it is true for $p_n$." also work? Because I think there are far more examples for the latter case.
Jun 12, 2017 at 8:28 comment added KConrad Another example is in the work on Serre's conjecture by Khare and Wintenberger. See the bottom of page 25 of arxiv.org/pdf/math/0412076.pdf.
Jun 12, 2017 at 8:20 comment added KConrad What is the motivation for this question: idle curiosity? In any case, the first proof of quadratic reciprocity by Gauss was an induction on the primes. Tate used that "ugly" proof in his calculation of $K_2(\mathbf Q)$, which is also an induction on primes (see Rosenberg's textbook on $K$-theory).
Jun 12, 2017 at 7:00 answer added Anthony Quas timeline score: 1
Jun 12, 2017 at 6:42 answer added Wlod AA timeline score: 2
Jun 12, 2017 at 4:57 comment added Arturo Magidin Not quite going through the regular sequence of primes in the usual order, but Baumslag proved that a finitely generated nilpotent group can be embedded in a locally nilpotent radicable group by taking a sequence of primes $p_1,p_2,\ldots,$ with the property that for all primes $p$ and all positive integers $m$, there exists an $n\gt m$ such that $p=p_n$ (so each prime occurs infinitely many times); and then adjoining $p_n$th roots to all elements already constructed to get the "next" group.
Jun 12, 2017 at 4:53 review Close votes
Jun 12, 2017 at 11:53
Jun 12, 2017 at 4:30 comment added Gerhard Paseman Or like mathoverflow.net/q/160403 ? Gerhard "Still Not Sure About This" Paseman, 2017.06.11.
Jun 12, 2017 at 4:21 comment added Wojowu Something like this?
Jun 12, 2017 at 4:06 comment added T. Amdeberhan You're right, I added a sentence to clarify a little bit.
Jun 12, 2017 at 4:05 history edited T. Amdeberhan CC BY-SA 3.0
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Jun 12, 2017 at 3:51 comment added Gerhard Paseman Fundamental theorem of arithmetic? Various statements on finite groups? Euclid's proof rearranged? What form of induction do you want? Gerhard "Can You Be More Specific?" Paseman, 2017.06.11.
Jun 12, 2017 at 3:24 history asked T. Amdeberhan CC BY-SA 3.0