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S Jun 11, 2017 at 20:58 history suggested CuriousUser CC BY-SA 3.0
Corrected the typo "$\tfrac{1-1}{2}$", into a "$\tfrac{q-1}{2}$"
Jun 11, 2017 at 19:41 review Suggested edits
S Jun 11, 2017 at 20:58
Jun 11, 2017 at 19:32 comment added CuriousUser How about $q=3$ (the case I am interested in)? In this case, if my computations are correct, $p_2$ can be written as a combination of $P^1(p_1)$ and $p_1^2$. Although you are right, in general this is clearly false, let me edit my question
Jun 11, 2017 at 19:22 history answered Oscar Randal-Williams CC BY-SA 3.0