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Jun 13, 2017 at 10:26 comment added Alexandre Your expression seems to come from the formula relating ${}_2F_2$ and ${}_0F_1$ and other similar identities. But the expressions of your polynomials are not clear yet.
Jun 11, 2017 at 20:14 comment added Carlo Beenakker Mathematica evaluates the integral for arbitrary real $n$ in terms of a hypergeometric function, which reduces to these explicit expressions for integer $n$.
Jun 11, 2017 at 19:33 comment added Alexandre Thanks! I would appreciate any reference or indication on how you got this. The coefficients $b_{n,0}$ seems to be $(-2)^nn!$.
Jun 11, 2017 at 16:49 history edited Carlo Beenakker CC BY-SA 3.0
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Jun 11, 2017 at 16:44 history answered Carlo Beenakker CC BY-SA 3.0