Timeline for Is there a characterization of the Hausdorff measures?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Jun 10, 2017 at 1:56 | comment | added | Pablo Shmerkin | The answer to the precise question is definitely no - the Cantor set of dimension $d$ has positive and finite $d$-dimensional packing measure, so a multiple of $d$-packing measure is a translation invariant measure that agrees with Hausdorff measure on the Cantor set yet is a (very) different measure. | |
| Jun 9, 2017 at 22:59 | answer | added | Emanuele Paolini | timeline score: 8 | |
| S Jun 9, 2017 at 13:21 | history | suggested | Martin Sleziak | CC BY-SA 3.0 |
typo in the title
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| Jun 9, 2017 at 12:55 | review | Suggested edits | |||
| S Jun 9, 2017 at 13:21 | |||||
| Jun 9, 2017 at 12:50 | history | edited | Phil-W | CC BY-SA 3.0 |
added 22 characters in body
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| Jun 9, 2017 at 12:42 | history | edited | Phil-W | CC BY-SA 3.0 |
added 199 characters in body
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| Jun 9, 2017 at 11:01 | comment | added | user95282 | @Dirk Or even $d=1$. | |
| Jun 9, 2017 at 2:01 | comment | added | Dirk | Not that I have any idea, but maybe the case of integer $d$ is simpler? | |
| Jun 8, 2017 at 23:36 | comment | added | Christian Remling | I very much doubt that there will be a "small" collection of such sets with "natural" values, whatever that means, unless $d=0$ or $n$. It works fine of course when restricted to suitable sets, for example the Cantor measure is the unique measure that gives each of the $2^n$ parts of the Cantor set (in the natural construction) its fair share of measure. | |
| Jun 8, 2017 at 22:25 | history | asked | Phil-W | CC BY-SA 3.0 |