Skip to main content
7 events
when toggle format what by license comment
Jun 14, 2017 at 6:33 comment added Sasha One possibility to find an answer is by using global Torelli theorem for K3 and analyzing possible embeddings of the lattice $16A_1$ into the second cohomology of a K3 ($3U + 2E_8$). Probably much information in this direction can be extracted from works of Nikulin.
Jun 9, 2017 at 9:43 comment added Bernie @Imeasy : Thank you. I knew that. But I don't know the behaviour of the 16 nodes, the tropes etc. with respect to the birational map of the singular Kummers $S_C$ and $S_{C'}$. So I can recover the curves, but what is their relation ship now? Must they be isomorphic?
Jun 9, 2017 at 8:54 comment added IMeasy You can reconstruct the genus 2 curve by taking the double cover of the Theta divisor (which is a conic in the singular Kummer - namely the intersection of the Kummer with one of the tropes) ramified along the 6 nodes contained therein.
Jun 8, 2017 at 14:58 comment added Bernie @Jason Starr : Okay. I phrased the question in terms of isomorphims and the K3 surfaces. My observation for Picard number one still remains. Can something be done for higher Picard numbers?
Jun 8, 2017 at 14:56 history edited Bernie CC BY-SA 3.0
added 327 characters in body; edited title
Jun 8, 2017 at 11:26 comment added Jason Starr For K3 surfaces $S$ and $S'$, for dense open subsets $U\subset S$ and $U'\subset S'$, for an isomorphism $\phi_U:U\xrightarrow{\cong} U'$, there exists a unique isomorphism $\phi:S\xrightarrow{\cong} S'$ whose restriction to $U$ equals $\phi_U$. So instead of working in the birational category, I suggest that you work in the biregular category.
Jun 8, 2017 at 10:08 history asked Bernie CC BY-SA 3.0