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Jun 3, 2017 at 12:25 history edited JIOCb CC BY-SA 3.0
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Jun 2, 2017 at 11:00 comment added Ben Barber You can get $k^{kn}$ by restricting to the largest coloured neighbourhood of an arbitrary vertex $kn$ times, then doing a second pass to get $n$ vertices where all the forward edges are the same colour.
Jun 1, 2017 at 16:04 history edited JIOCb
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Jun 1, 2017 at 15:50 review First posts
Jun 1, 2017 at 16:02
Jun 1, 2017 at 15:50 history asked JIOCb CC BY-SA 3.0