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Jun 5, 2010 at 2:34 comment added Steve Huntsman books.google.com/books?id=ACzC8sHg3jEC
Jun 4, 2010 at 23:26 comment added Mikola Note: one can define some "convolution-like" operators on manifolds or graphs. For example, some people take the mesh/graph Laplacian operator, and consider its eigenvectors to be the appropriate generalization of Fourier series. If this is true, then one could work backwards from the convolution theorem and define the convolution of two function to be the pointwise multiplication of the eigen functions. However, this forces all convolution to be commutative, which is not always desirable (for example in the case of the sphere...)
Jun 4, 2010 at 22:31 history asked Mikola CC BY-SA 2.5