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Jul 24, 2016 at 12:52 comment added user94803 Reemphasizing Carnahan's comment, a plane curve must have genus of the form $(d-1)(d-2)/2$, by the genus-degree formula. Hence, in particular, an algebraic curve of genus $2$ cannot be embedded into the plane.
Jan 20, 2011 at 2:35 comment added timur Is the result you alluded to called Riemann-Roch?
Oct 27, 2009 at 0:18 comment added Ilya Nikokoshev Yes, I corrected it to refer to non-smooth Riemann surfaces.
Oct 27, 2009 at 0:17 history edited Ilya Nikokoshev CC BY-SA 2.5
corrected
Oct 27, 2009 at 0:10 comment added S. Carnahan Most higher-genus curves cannot be smoothly embedded in the plane, but they fit nicely in three-space.
Oct 26, 2009 at 23:35 history edited Ilya Nikokoshev CC BY-SA 2.5
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Oct 26, 2009 at 23:10 history answered Ilya Nikokoshev CC BY-SA 2.5